-16t^2+10=10

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Solution for -16t^2+10=10 equation: 



-16t^2+10=10

We move all terms to the left:

-16t^2+10-(10)=0

We add all the numbers together, and all the variables

-16t^2=0

a = -16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-16)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{-32}=0$

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